What is the extreme f(x)=x^4-98x^2+2401 ?

The extreme f(x)=x^4-98x^2+2401 is Minimum(-7,0),Maximum(0,2401),Minimum(7,0)

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extreme f(x)=x^4-98x^2+2401

extreme points

f (x) = x^{4} - 98 x^{2} + 2401

Minimum (- 7, 0), Maximum (0, 2401), Minimum (7, 0)

Solution steps

f^{'} (x) = 4 x^{3} - 196 x

Find intervals:

Decreasing

: - \infty < x < - 7,

Increasing

: - 7 < x < 0,

Decreasing

: 0 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 7

into

x^{4} - 98 x^{2} + 2401 : 0

Minimum (- 7, 0)

Plug

x = 0

into

x^{4} - 98 x^{2} + 2401 : 2401

Maximum (0, 2401)

Plug

x = 7

into

x^{4} - 98 x^{2} + 2401 : 0

Minimum (7, 0)

Minimum (- 7, 0), Maximum (0, 2401), Minimum (7, 0)

r an g e 9 - 3^{x}

d o main f (x) = 4 x^{4} - 1

d o main \frac{1}{x ^{2} - 6 x}

s l o p e - 2 x + y = 4

in v erse \frac{x}{9 x - 8}

What is the extreme f(x)=x^4-98x^2+2401 ?
The extreme f(x)=x^4-98x^2+2401 is Minimum(-7,0),Maximum(0,2401),Minimum(7,0)