What is the extreme f(x)=x^3-3/2 x^2 ?

The extreme f(x)=x^3-3/2 x^2 is Maximum(0,0),Minimum(1,-1/2)

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extreme f(x)=x^3-3/2 x^2

extreme points

f (x) = x^{3} - \frac{3}{2} x^{2}

Maximum (0, 0), Minimum (1, - \frac{1}{2})

Solution steps

f^{'} (x) = 3 x^{2} - 3 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 0

into

x^{3} - \frac{3}{2} x^{2} : 0

Maximum (0, 0)

Plug

x = 1

into

x^{3} - \frac{3}{2} x^{2} : - \frac{1}{2}

Minimum (1, - \frac{1}{2})

Maximum (0, 0), Minimum (1, - \frac{1}{2})

sy mm e t ry x^{2} - 7 x + 10

e x t re m e - 2 - x + x^{2}

in t erce pt s f (x) = y - \frac{3}{2}

in v erse f (x) = - \frac{2}{5} x^{6} + 8

a sy m pt o t es y = \frac{5 e ^{x}}{e ^{x} - 7}

What is the extreme f(x)=x^3-3/2 x^2 ?
The extreme f(x)=x^3-3/2 x^2 is Maximum(0,0),Minimum(1,-1/2)