What is the inverse of f(x)=x^2+3x+2 ?

The inverse of f(x)=x^2+3x+2 is (-3+sqrt(4x+1))/2 ,(-3-sqrt(4x+1))/2

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inverse of f(x)=x^2+3x+2

inverse

f (x) = x^{2} + 3 x + 2

\frac{- 3 + 4 x + 1}{2}, \frac{- 3 - 4 x + 1}{2}

Solution steps

y = x^{2} + 3 x + 2

Replace

x

with

y

x = y^{2} + 3 y + 2

Solve for

y, x = y^{2} + 3 y + 2

\frac{- 3 + 4 x + 1}{2}, \frac{- 3 - 4 x + 1}{2}

mi d p o in t (2, - 8), (7, - 4)

d o main f (x) = \frac{∣ x ∣}{x}

a sy m pt o t es \frac{x ^{2} + x - 12}{x - 3}

in t erce pt s \frac{2 x}{x ^{2} - 1}

r an g e f (x) = x^{2} - 4 x - 1

What is the inverse of f(x)=x^2+3x+2 ?
The inverse of f(x)=x^2+3x+2 is (-3+sqrt(4x+1))/2 ,(-3-sqrt(4x+1))/2