What is the domain of f(x)= 1/(\frac{1){sqrt(x)}} ?

The domain of f(x)= 1/(\frac{1){sqrt(x)}} is x>0

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domain of f(x)= 1/(\frac{1){sqrt(x)}}

domain

f (x) = \frac{1}{\frac{1}{x}}

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

d o main y = 3 x^{4} + 9

r an g e f (x) = x - 2

sy mm e t ry y = - x^{2} + 4 x - 2

d o main y = \frac{2 x}{( x - 2 ) ( x + 1 )}

r an g e f (x) = - x + 2 - 3

What is the domain of f(x)= 1/(\frac{1){sqrt(x)}} ?
The domain of f(x)= 1/(\frac{1){sqrt(x)}} is x>0