What is the critical (x-4)/(3x-x^2) ?

The critical (x-4)/(3x-x^2) is x=2,x=6

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critical (x-4)/(3x-x^2)

critical points

\frac{x - 4}{3 x - x ^{2}}

x = 2, x = 6

Solution steps

\frac{x - 4}{3 x - x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2, x = 6, x = 0, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x - 4}{3 x - x ^{2}} : x < 0 or 0 < x < 3 or x > 3

\frac{x - 4}{3 x - x ^{2}}

is not defined at

x = 0, x = 3

, therefore:

x = 2, x = 6