What is the inverse of y=12x-4x^2 ?

The inverse of y=12x-4x^2 is -(-3+sqrt(-x+9))/2 ,(sqrt(-x+9)+3)/2

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inverse of y=12x-4x^2

inverse

y = 12 x - 4 x^{2}

- \frac{- 3 + - x + 9}{2}, \frac{- x + 9 + 3}{2}

Solution steps

y = 12 x - 4 x^{2}

Replace

x

with

y

x = 12 y - 4 y^{2}

Solve for

y, x = 12 y - 4 y^{2}

- \frac{- 3 + - x + 9}{2}, \frac{- x + 9 + 3}{2}

y = x + 6 - 7

y = x + 4

f (x) = \frac{2 x - 1}{2}

\frac{x - x ( 2 x ^{2} - 5 )}{2 x ^{2} - 5}

1 + 2 x

What is the inverse of y=12x-4x^2 ?
The inverse of y=12x-4x^2 is -(-3+sqrt(-x+9))/2 ,(sqrt(-x+9)+3)/2