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Popular Functions >

range of 2x^2-5

Solution

range

2 x^{2} - 5

Solution

f (x) \geq - 5

+1

Interval Notation

[- 5, \infty)

Solution steps

Vertex of

2 x^{2} - 5 :

Minimum

(0, - 5)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (0, - 5)

f (x) \geq - 5

Graph

Popular Examples

asymptotes of f(x)=xe^{-3x}

a sy m pt o t es f (x) = x e^{- 3 x}

asymptotes of f(x)=(-4x^2+7x-2)/(x^2+5)

a sy m pt o t es f (x) = \frac{- 4 x ^{2} + 7 x - 2}{x ^{2} + 5}

domain of f(x)= 5/(sqrt(x-3))

d o main f (x) = \frac{5}{x - 3}

shift 5sin(2x+pi)

s hi f t 5 sin (2 x + π)

parity y=(2x^2-3x+1)/(sqrt(3x^4+4x^2+2))

p a r i t y y = \frac{2 x ^{2} - 3 x + 1}{3 x ^{4} + 4 x ^{2} + 2}

Frequently Asked Questions (FAQ)

What is the range of 2x^2-5 ?
The range of 2x^2-5 is f(x)>=-5