What is the inverse of f(x)=\sqrt[3]{(-n+3)/2} ?

The inverse of f(x)=\sqrt[3]{(-n+3)/2} is -2n^3+3

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inverse of f(x)=\sqrt[3]{(-n+3)/2}

inverse

f (x) = 3 \frac{- n + 3}{2}

- 2 n^{3} + 3

Solution steps

y = 3 \frac{- n + 3}{2}

Replace

n

with

y

n = 3 \frac{- y + 3}{2}

Solve for

y, n = 3 \frac{- y + 3}{2}

- 2 n^{3} + 3

r an g e \frac{3 x}{x ^{2} - 1}

in v erse y = 3 3 x + 1

a sy m pt o t es 46

d o main \frac{5 x - 2}{x + 1}

in f l ec t i o n 16 x^{4} - 96 x^{2}

What is the inverse of f(x)=\sqrt[3]{(-n+3)/2} ?
The inverse of f(x)=\sqrt[3]{(-n+3)/2} is -2n^3+3