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midpoint
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domain of (\sqrt[8]{x-2})/(log_{4)(5-x)}domain of y=sqrt(8x+1)midpoint (-1,-1),(-7,-9)symmetry y=x^2-8x+12inverse of f(x)=4x^3+7
Frequently Asked Questions (FAQ)
What is the midpoint (1,-1),(-10,2) ?
The midpoint (1,-1),(-10,2) is (-9/2 , 1/2)