extreme x^2ln(x/6)

Lösung

extrempunkte

x^{2} ln (\frac{x}{6})

Minimum (\frac{6}{e}, - \frac{18}{e})

Schritte zur Lösung

f^{'} (x) = 2 x ln (\frac{x}{6}) + x

Intervalle finden:

Absteigend

: 0 < x < \frac{6}{e},

Ansteigend

: \frac{6}{e} < x < \infty

Stecke

x = \frac{6}{e}

x^{2} ln (\frac{x}{6}) : - \frac{18}{e}

Minimum (\frac{6}{e}, - \frac{18}{e})

d o main \frac{3}{\frac{2}{x} - 1}

in f l ec t i o n f (x) = x^{4} + 4 x^{3} - 18 x^{2}

in t erce pt s f (x) = 6 x^{4} + 3 x^{3} - 9 x^{2}

in t erce pt s f (x) = \frac{sin ( 4 x )}{2 x}

a sy m pt o t es f (x) = \frac{x ^{2}}{x - 3}