What is the monotone f(x)=x^4-8x+16 ?

The monotone f(x)=x^4-8x+16 is Decreasing:-infinity <x<\sqrt[3]{2},Increasing:\sqrt[3]{2}<x<infinity

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monotone f(x)=x^4-8x+16

monotone intervals

f (x) = x^{4} - 8 x + 16

Decreasing : - \infty < x < 32, Increasing : 32 < x < \infty

Solution steps

f^{'} (x) = 4 x^{3} - 8

Find intervals:

Decreasing

: - \infty < x < 32,

Increasing

: 32 < x < \infty

Decreasing : - \infty < x < 32, Increasing : 32 < x < \infty

a sy m pt o t es \frac{( x + 1 )}{( x + 2 ) ( x - 3 )}

in v erse f (x) = \frac{2 x + 1}{3 x}

p er p e n d i c u l a r y = x, (6, 1)

in t erce pt s f (x) = 3 y + 2 x = - x + 5

a sy m pt o t es f (x) = (\frac{2 x}{x + 2})

What is the monotone f(x)=x^4-8x+16 ?
The monotone f(x)=x^4-8x+16 is Decreasing:-infinity <x<\sqrt[3]{2},Increasing:\sqrt[3]{2}<x<infinity