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symmetry
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inverse of f(x)=((x+1))/((4x+1))critical e^{-0.5x^2}inverse of f(x)=4x^2+1perpendicular x-4=0f(x)=x^3-1
Frequently Asked Questions (FAQ)
What is the symmetry y=-1/2 (x+3)^2+2 ?
The symmetry y=-1/2 (x+3)^2+2 is y=-3