定义域 log_{2}(2x-2)-3

解答

定义域

lo g_{2} (2 x - 2) - 3

x > 1

间隔符号

(1, \infty)

求解步骤

对于对数找到正值:

x > 1

函数定义域

x > 1

e x t re m e f (x) = 310 x^{3} - x^{2} - 8 x + 48

in v erse f (x) = x^{2} - 10 x

cr i t i c a l f (x) = 2 x + 5 cos (x)

in v erse f (x) = 3 + x^{3}

d o main f (x) = \frac{x + 1}{x ^{2} - 3 x + 2}