What is the inverse of f(x)=((2x+1))/(x-3) ?

The inverse of f(x)=((2x+1))/(x-3) is (1+3x)/(x-2)

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inverse of f(x)=((2x+1))/(x-3)

inverse

f (x) = \frac{( 2 x + 1 )}{x - 3}

\frac{1 + 3 x}{x - 2}

Solution steps

y = \frac{2 x + 1}{x - 3}

Replace

x

with

y

x = \frac{2 y + 1}{y - 3}

Solve for

y, x = \frac{2 y + 1}{y - 3}

\frac{1 + 3 x}{x - 2}

f (x) = e^{6 x - 5}

g (x) = \frac{3 x - 8}{8 x + 1}

y = 6 x

y = 1

x + 7

What is the inverse of f(x)=((2x+1))/(x-3) ?
The inverse of f(x)=((2x+1))/(x-3) is (1+3x)/(x-2)