What is the shift f(x)=-4sin(6x+pi/2) ?

The shift f(x)=-4sin(6x+pi/2) is Phase:-pi/(12), Vertical:0

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shift f(x)=-4sin(6x+pi/2)

shift

f (x) = - 4 sin (6 x + \frac{π}{2})

Phase : - \frac{π}{12}, Vertical : 0

Solution steps

f (x) = - 4 sin (6 x + \frac{π}{2})

g (B x - C) = sin (6 x + \frac{π}{2}), B = 6, C = - \frac{π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{2}}{6}

- \frac{π}{12}

The vertical shift

D

0

0

y = - 2 x + 5

(\frac{3}{2 ,} \frac{1}{2}) m = 5

f (x) = (10 - 3 x)^{\frac{5}{2}}

3 x + 2

f (x) = 4 x^{2} + x + 5

What is the shift f(x)=-4sin(6x+pi/2) ?
The shift f(x)=-4sin(6x+pi/2) is Phase:-pi/(12), Vertical:0