What is the domain of f(x)= 1/((1-x^2)^{1/2)-1} ?

The domain of f(x)= 1/((1-x^2)^{1/2)-1} is -1<= x<0\lor 0<x<= 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/((1-x^2)^{1/2)-1}

domain

f (x) = \frac{1}{( 1 - x ^{2} ) ^{\frac{1}{2}} - 1}

- 1 \leq x < 0 or 0 < x \leq 1

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 \leq x < 0 or 0 < x \leq 1

- \frac{1}{x ^{2}}

f (x) = x^{c o s (x)}

f (x) = (x - 5) (x + 5)

f (x) = - x^{3} + 4

4 x + 5 y = - 5

What is the domain of f(x)= 1/((1-x^2)^{1/2)-1} ?
The domain of f(x)= 1/((1-x^2)^{1/2)-1} is -1<= x<0\lor 0<x<= 1