What is the asymptotes of f(x)=(t-1)/(t^2+1) ?

The asymptotes of f(x)=(t-1)/(t^2+1) is Horizontal: x=0

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asymptotes of f(x)=(t-1)/(t^2+1)

asymptotes

f (x) = \frac{t - 1}{t ^{2} + 1}

Horizontal : x = 0

Solution steps

Vertical asymptotes of

\frac{t - 1}{t ^{2} + 1} :

None

Horizontal Asymptotes of

\frac{t - 1}{t ^{2} + 1} : x = 0

Slant Asymptotes of

\frac{t - 1}{t ^{2} + 1} :

None

Horizontal : x = 0

a sy m pt o t es f (x) = - 4 cot (3 x)

in v erse f (x) = 4 y - 3

s hi f t f (x) = 9 cos (\frac{1}{3} π x + π) - 2

r an g e ln (x + 6)

cr i t i c a l f (x) = 3 x^{\frac{2}{3}} - 2 x

What is the asymptotes of f(x)=(t-1)/(t^2+1) ?
The asymptotes of f(x)=(t-1)/(t^2+1) is Horizontal: x=0