What is the critical x^4-12x^3+48x^2-64x ?

The critical x^4-12x^3+48x^2-64x is x=1,x=4

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critical x^4-12x^3+48x^2-64x

critical points

x^{4} - 12 x^{3} + 48 x^{2} - 64 x

x = 1, x = 4

Solution steps

x^{4} - 12 x^{3} + 48 x^{2} - 64 x

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 4

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 12 x^{3} + 48 x^{2} - 64 x : - \infty < x < \infty

All critical points are in domain

x = 1, x = 4

\frac{2 x ^{2} - 3}{x + 2}

f (x) = 3 x^{2}

16 - 8 x + x^{2}

x^{2} + 6

\frac{x ( x - 5 )}{x ^{2} - 9}

What is the critical x^4-12x^3+48x^2-64x ?
The critical x^4-12x^3+48x^2-64x is x=1,x=4