What is the domain of f(x)=(x+1)^2-4 ?

The domain of f(x)=(x+1)^2-4 is -infinity <x<infinity

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domain of f(x)=(x+1)^2-4

domain

f (x) = (x + 1)^{2} - 4

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = x^{5} - 3 x^{3} + 7

4 x^{3} - 1

f (x) = 9 - 5 e^{x}

f (x) = \frac{1}{5} x^{3} - 4

f (x) = - \frac{1}{x ^{2} - 81}

What is the domain of f(x)=(x+1)^2-4 ?
The domain of f(x)=(x+1)^2-4 is -infinity <x<infinity