What is the perpendicular y= 1/3 x ?

The perpendicular y= 1/3 x is y=-3x+b

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perpendicular y= 1/3 x

perpendicular

y = \frac{1}{3} x

y = - 3 x + b

Solution steps

Find the slope of

y = \frac{1}{3} x : m = \frac{1}{3}

Compute the slope of the perpendicular line:

m_{p} = - 3

Line with slope m=

- 3 : y = - 3 x + b

y = - 3 x + b

f (x) = 9 x

\frac{2}{5} x - 6

f (x) = 2 csc (\frac{x}{3})

f (x) = \frac{- x}{x + 4}

5^{x} + 3