振幅 5cos(6x+pi/2)

解答

振幅

5 cos (6 x + \frac{π}{2})

5

求解步骤

f (x) = 5 cos (6 x + \frac{π}{2}), A = 5

因此，振幅 |A| 为

5

5

s l o p e in t erce pt 3 x + 2 y = 10

d o main x^{2} - 121

r an g e \frac{x}{x ^{2} - 16}

r an g e f (x) = \frac{3 x ^{2} + 2 x - 1}{6 x ^{2} - 7 x - 3}

v er t i ces y = 2 x^{2} - 12 x - 2