inflection f(x)=-x^4+3x^2-4

Lösung

wendepunkte

f (x) = - x^{4} + 3 x^{2} - 4

(- \frac{1}{2}, - \frac{11}{4}), (\frac{1}{2}, - \frac{11}{4})

Schritte zur Lösung

f^{''} (x) = - 12 x^{2} + 6

Intervalle finden:

Konkav fallend

: - \infty < x < - \frac{1}{2},

Konkav steigend

: - \frac{1}{2} < x < \frac{1}{2},

Konkav fallend

: \frac{1}{2} < x < \infty

Stecke

x = - \frac{1}{2}

- x^{4} + 3 x^{2} - 4 : - \frac{11}{4}

(- \frac{1}{2}, - \frac{11}{4})

Stecke

x = \frac{1}{2}

- x^{4} + 3 x^{2} - 4 : - \frac{11}{4}

(\frac{1}{2}, - \frac{11}{4})

(- \frac{1}{2}, - \frac{11}{4}), (\frac{1}{2}, - \frac{11}{4})

in v erse f (x) = \frac{1}{x - 1} - 3

in v erse 8 - 7 x

d o main f (x) = 3 x - 3

d o main h (x) = \frac{1}{4 x ^{2} - 5 x}

in v erse f (x) = - \frac{1}{x - 2} + 1