What is the domain of ((x^2+1)sqrt(x^2-16))/(x^2) ?

The domain of ((x^2+1)sqrt(x^2-16))/(x^2) is x = 4

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domain of ((x^2+1)sqrt(x^2-16))/(x^2)

domain

\frac{( x ^{2} + 1 ) x ^{2} - 16}{x ^{2}}

x \leq - 4 or x \geq 4

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \leq - 4 or x \geq 4

y = 3^{x} + 2

f (x) = 5 x^{2} + 6

f (x) = 25 x^{2}

y = (\frac{1}{2})^{x}

sin (2 x) + x

What is the domain of ((x^2+1)sqrt(x^2-16))/(x^2) ?
The domain of ((x^2+1)sqrt(x^2-16))/(x^2) is x<=-4\lor x>= 4