What is the inverse of f(x)=((x^2-4))/(6x^2) ?

The inverse of f(x)=((x^2-4))/(6x^2) is sqrt(-4/(6x-1)),-sqrt(-4/(6x-1))

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inverse of f(x)=((x^2-4))/(6x^2)

inverse

f (x) = \frac{( x ^{2} - 4 )}{6 x ^{2}}

- \frac{4}{6 x - 1}, - - \frac{4}{6 x - 1}

Solution steps

y = \frac{x ^{2} - 4}{6 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 4}{6 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 4}{6 y ^{2}}

- \frac{4}{6 x - 1}, - - \frac{4}{6 x - 1}

f (x) = 3 (\frac{x - 9}{2}) + 20

(- 4, 7), (- 10, 13)

f (x) = \frac{x - 7}{( x - 7 ) ( x - 5 )}

2 x + 3

6 cos (\frac{x}{2})

What is the inverse of f(x)=((x^2-4))/(6x^2) ?
The inverse of f(x)=((x^2-4))/(6x^2) is sqrt(-4/(6x-1)),-sqrt(-4/(6x-1))