渐近线 h(t)=(t^2-4t)/(t^4-256)

解答

渐近线

h (t) = \frac{t ^{2} - 4 t}{t ^{4} - 256}

垂直 : t = - 4, 水平 : y = 0

求解步骤

\frac{t ^{2} - 4 t}{t ^{4} - 256}

的垂直渐近线:

t = - 4

\frac{t ^{2} - 4 t}{t ^{4} - 256}

的水平渐近线:

y = 0

Slant Asymptotes of

\frac{t ^{2} - 4 t}{t ^{4} - 256} :

无

垂直 : t = - 4, 水平 : y = 0

s l o p e in t erce pt 3 x + 12 y = 24

in t erce pt s f (x) = 3 x - 4

d o main f (x) = \frac{1}{x - 1}

in v erse \frac{6 x - 1}{2 x + 5}

d o main f (x) = \frac{9}{x}