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Popular Functions >

range of 2x^2+5x+10

Solution

range

Solution

f (x) \geq \frac{55}{8}

+1

Interval Notation

Solution steps

Vertex of

2 x^{2} + 5 x + 10 :

Minimum

(- \frac{5}{4}, \frac{55}{8})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (- \frac{5}{4}, \frac{55}{8})

f (x) \geq \frac{55}{8}

Graph

Popular Examples

symmetry y=x^2+4x+2

asymptotes of f(x)=(x-8)/(x^2-64)

intercepts of y=1-x^2

simplify (2.1)(-6.7)

line (6,25.4),(19,24.1)

Frequently Asked Questions (FAQ)

What is the range of 2x^2+5x+10 ?
The range of 2x^2+5x+10 is f(x)>= 55/8