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midpoint
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domain of f(x)=sqrt((5-4x-x^2)/(x+3))symmetry-(x^2)/(10)+(9x)/(10)+11/5parity f(x)=sin(ln(-(sqrt(3))/2))intercepts of f(x)=(6x)/(x^2+16)asymptotes of f(x)=(x^2-x)/(-x+1)
Frequently Asked Questions (FAQ)
What is the midpoint (6,-3),(7,-2) ?
The midpoint (6,-3),(7,-2) is (13/2 ,-5/2)