求反函数 4^{x-2}+1

解答

求反函数

4^{x - 2} + 1

\frac{ln ( x - 1 )}{2 ln ( 2 )} + 2

求解步骤

y = 4^{x - 2} + 1

用

y

替代

x

x = 4^{y - 2} + 1

求解

y, x = 4^{y - 2} + 1

\frac{ln ( x - 1 )}{2 ln ( 2 )} + 2

in v erse f (x) = \frac{5}{2 - x}

f (x) = \frac{∣ x ∣}{x}

cr i t i c a l f (x) = 126 w^{2} - 2 w^{3}

mi d p o in t (2, 5), (- 2, - 3)

a sy m pt o t es \frac{- 2 x + 8}{x + 2}