extreme f(x)=0.00397t^2-0.593t+33.718

Lösung

extrempunkte

f (x) = 0.00397 t^{2} - 0.593 t + 33.718

Minimum (\frac{0.593}{0.00794}, 11.57385 \dots)

Schritte zur Lösung

f^{'} (t) = 0.00794 t - 0.593

Intervalle finden:

Absteigend

: - \infty < t < \frac{0.593}{0.00794},

Ansteigend

: \frac{0.593}{0.00794} < t < \infty

Stecke

t = \frac{0.593}{0.00794}

0.00397 t^{2} - 0.593 t + 33.718 : 11.57385 \dots

Minimum (\frac{0.593}{0.00794}, 11.57385 \dots)

e x t re m e f (x) = f (x) = e x - x, - 4 \leq x \leq 2

e x t re m e f (x) = 4 x^{2} - 48 x + 190

e x t re m e f (x, y) = e^{9 x^{2} + 6 y^{2} + 1}

e x t re m e f (x) = (\frac{3 - cos ( θ )}{sin ( θ )})

e x t re m e f (x y) = - x^{3} - y^{2} + 3 x - 2 y