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Beliebt Funktionen >

extreme f(x)=-8x^3+110x^2-143x+590

Lösung

extrempunkte

f (x) = - 8 x^{3} + 110 x^{2} - 143 x + 590

Lösung

Minimum (\frac{55 - 2167}{12}, \frac{95590 - 2167 2167}{108} + 590), Maximum (\frac{55 + 2167}{12}, \frac{95590 + 2167 2167}{108} + 590)

Schritte zur Lösung

f^{'} (x) = - 24 x^{2} + 220 x - 143

Intervalle finden:

Absteigend

: - \infty < x < \frac{- 2167 + 55}{12},

Ansteigend

: \frac{- 2167 + 55}{12} < x < \frac{2167 + 55}{12},

Absteigend

: \frac{2167 + 55}{12} < x < \infty

Stecke

x = \frac{55 - 2167}{12}

in

- 8 x^{3} + 110 x^{2} - 143 x + 590 : \frac{95590 - 2167 2167}{108} + 590

Minimum (\frac{55 - 2167}{12}, \frac{95590 - 2167 2167}{108} + 590)

Stecke

x = \frac{55 + 2167}{12}

in

- 8 x^{3} + 110 x^{2} - 143 x + 590 : \frac{95590 + 2167 2167}{108} + 590

Maximum (\frac{55 + 2167}{12}, \frac{95590 + 2167 2167}{108} + 590)

Minimum (\frac{55 - 2167}{12}, \frac{95590 - 2167 2167}{108} + 590), Maximum (\frac{55 + 2167}{12}, \frac{95590 + 2167 2167}{108} + 590)

Graph

Beliebte Beispiele

extreme f(x)=x^4+4x^3+15,-4<= x<= 1

e x t re m e f (x) = x^{4} + 4 x^{3} + 15, - 4 \leq x \leq 1

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extreme y=-2x^2+12x-8

e x t re m e y = - 2 x^{2} + 12 x - 8