extreme 125x^3-15x+1

Lösung

extrempunkte

125 x^{3} - 15 x + 1

Maximum (- \frac{1}{5}, 3), Minimum (\frac{1}{5}, - 1)

Schritte zur Lösung

f^{'} (x) = 375 x^{2} - 15

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{1}{5},

Absteigend

: - \frac{1}{5} < x < \frac{1}{5},

Ansteigend

: \frac{1}{5} < x < \infty

Stecke

x = - \frac{1}{5}

125 x^{3} - 15 x + 1 : 3

Maximum (- \frac{1}{5}, 3)

Stecke

x = \frac{1}{5}

125 x^{3} - 15 x + 1 : - 1

Minimum (\frac{1}{5}, - 1)

Maximum (- \frac{1}{5}, 3), Minimum (\frac{1}{5}, - 1)

e x t re m e f (x) = x^{2} + x y + 2 x + 2 y + 3

e x t re m e f (x) = x (e^{x})

e x t re m e f (x, y) = 2 x^{2} + 2 y^{2} - x^{4} - y^{4} + 3

e x t re m e sin (2 x) + cos (2 x)

e x t re m e f (x) = \frac{x}{( x ^{2} + 4 )}