de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Funktionen >

extreme ((pi+4)x^2-640x+25600)/pi

Lösung

extrempunkte

\frac{( π + 4 ) x ^{2} - 640 x + 25600}{π}

Lösung

Minimum (\frac{320}{π + 4}, \frac{25600}{π + 4})

Schritte zur Lösung

f^{'} (x) = 2 x + \frac{8 x - 640}{π}

Intervalle finden:

Absteigend

: - \infty < x < \frac{320}{π + 4},

Ansteigend

: \frac{320}{π + 4} < x < \infty

Stecke

x = \frac{320}{π + 4}

in

\frac{( π + 4 ) x ^{2} - 640 x + 25600}{π} : \frac{25600}{π + 4}

Minimum (\frac{320}{π + 4}, \frac{25600}{π + 4})

Graph

Beliebte Beispiele

extreme f(x)=x(22-x)

e x t re m e f (x) = x (22 - x)

y(C,t)=C_{2}e^{-6t}

y (C, t) = C_{2} e^{- 6 t}

extreme f(x)=x^2-20x+104

e x t re m e f (x) = x^{2} - 20 x + 104

extreme f(x)=e^{x^2+5y^2+12}

e x t re m e f (x) = e^{x^{2} + 5 y^{2} + 12}

extreme f(x,y)=ln(4-x^2-y^2)-1/(1-x^2)

e x t re m e f (x, y) = ln (4 - x^{2} - y^{2}) - \frac{1}{1 - x ^{2}}