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Frequently Asked Questions (FAQ)
What is the extreme f(x)=(x^2-16)^{1/9},-5<= x<= 4 ?
- The extreme f(x)=(x^2-16)^{1/9},-5<= x<= 4 is Maximum(-5,9^{1/9}),Minimum(0,-16^{1/9}),Maximum(4,0)