extreme f(x)=1-(x-2)^{4/5}

Lösung

extrempunkte

f (x) = 1 - (x - 2)^{\frac{4}{5}}

Maximum (2, 1)

Schritte zur Lösung

f^{'} (x) = - \frac{4}{5 ( x - 2 ) ^{\frac{1}{5}}}

Intervalle finden:

Ansteigend

: - \infty < x < 2,

Absteigend

: 2 < x < \infty

Stecke

x = 2

1 - (x - 2)^{\frac{4}{5}} : 1

Maximum (2, 1)

e x t re m e f (x) = 3 x^{3} - 9 x^{2} - 315 x + 7

e x t re m e f (x) = \frac{5}{x ^{2} + 1} - 1

e x t re m e 2 x^{3} + 6 x^{2} - 90 x + 7, - 5 \leq x \leq 6

e x t re m e f (x) = - \frac{5}{4} x^{2} + \frac{5}{2} x + \frac{7}{4}

e x t re m e f (x, y) = x + y - \frac{3}{2} (x^{2} + y^{2} + 1)