extreme g(x)= 1/9 x^9-x

Lösung

extrempunkte

g (x) = \frac{1}{9} x^{9} - x

Maximum (- 1, \frac{8}{9}), Minimum (1, - \frac{8}{9})

Schritte zur Lösung

f^{'} (x) = x^{8} - 1

Intervalle finden:

Ansteigend

: - \infty < x < - 1,

Absteigend

: - 1 < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = - 1

\frac{1}{9} x^{9} - x : \frac{8}{9}

Maximum (- 1, \frac{8}{9})

Stecke

x = 1

\frac{1}{9} x^{9} - x : - \frac{8}{9}

Minimum (1, - \frac{8}{9})

Maximum (- 1, \frac{8}{9}), Minimum (1, - \frac{8}{9})

e x t re m e f (x, y) = \frac{- x - ln ( x ^{2} + y ^{2} - 81 )}{666}

e x t re m e f (x, y) = 7 - x^{4} + 2 x^{2} - y^{2}

e x t re m e - x^{3} + 27 x - 58

e x t re m e f (x) = 2 x^{3} - 42 x^{2} + 270 x + 10

e x t re m e - x^{3} + 27 x - 55