extreme f(x)=((x^2+121))/(2x)

Lösung

extrempunkte

f (x) = \frac{( x ^{2} + 121 )}{2 x}

Maximum (- 11, - 11), Minimum (11, 11)

Schritte zur Lösung

f^{'} (x) = \frac{x ^{2} - 121}{2 x ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < - 11,

Absteigend

: - 11 < x < 0,

Absteigend

: 0 < x < 11,

Ansteigend

: 11 < x < \infty

Stecke

x = - 11

\frac{x ^{2} + 121}{2 x} : - 11

Maximum (- 11, - 11)

Stecke

x = 11

\frac{x ^{2} + 121}{2 x} : 11

Minimum (11, 11)

Maximum (- 11, - 11), Minimum (11, 11)

e x t re m e f (x) = - 7 + 12 x - 3 x^{2}

e x t re m e y = \frac{x ^{2} - 2 x + 1}{x ^{2} + 3}

e x t re m e f (x) = \frac{2 + 4 x ^{2}}{1 - 3 x}

e x t re m e f (x, y) = 3 x - 5 y - 2

e x t re m e f (x) = x^{3} - 2 x^{2} - 6 x + 1