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Frequently Asked Questions (FAQ)
What is the extreme f(x)=(x^3)/3-x^2-3x-1,2<= x<= 7 ?
- The extreme f(x)=(x^3)/3-x^2-3x-1,2<= x<= 7 is Maximum(2,-25/3),Minimum(3,-10),Maximum(7, 130/3)