What is the extreme f(x)=5e^{x^2-10x} ?

The extreme f(x)=5e^{x^2-10x} is Minimum(5, 5/(e^{25)})

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extreme f(x)=5e^{x^2-10x}

extreme points

f (x) = 5 e^{x^{2} - 10 x}

Minimum (5, \frac{5}{e ^{25}})

Solution steps

f^{'} (x) = 5 e^{x^{2} - 10 x} (2 x - 10)

Find intervals:

Decreasing

: - \infty < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 5

into

5 e^{x^{2} - 10 x} : \frac{5}{e ^{25}}

Minimum (5, \frac{5}{e ^{25}})

f (x) = 2 x^{2} (x^{2} - 2)

- 3 x + ln (x)

f (x) = 52 (70 - x)

f (x) = x^{11} - 9 x^{7} + 5 x - 3

f (x) = x^{2} + y^{2} - 2 x - 2 y + 3

What is the extreme f(x)=5e^{x^2-10x} ?
The extreme f(x)=5e^{x^2-10x} is Minimum(5, 5/(e^{25)})