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Popular >

extreme 2x^2+8x+12

Solution

extreme points

2 x^{2} + 8 x + 12

Solution

Minimum (- 2, 4)

Solution steps

f^{'} (x) = 4 x + 8

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

2 x^{2} + 8 x + 12 : 4

Minimum (- 2, 4)

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Frequently Asked Questions (FAQ)

What is the extreme 2x^2+8x+12 ?
The extreme 2x^2+8x+12 is Minimum(-2,4)