extreme-x^3+x^2+x+8

Lösung

extrempunkte

- x^{3} + x^{2} + x + 8

Minimum (- \frac{1}{3}, \frac{211}{27}), Maximum (1, 9)

Schritte zur Lösung

f^{'} (x) = - 3 x^{2} + 2 x + 1

Intervalle finden:

Absteigend

: - \infty < x < - \frac{1}{3},

Ansteigend

: - \frac{1}{3} < x < 1,

Absteigend

: 1 < x < \infty

Stecke

x = - \frac{1}{3}

- x^{3} + x^{2} + x + 8 : \frac{211}{27}

Minimum (- \frac{1}{3}, \frac{211}{27})

Stecke

x = 1

- x^{3} + x^{2} + x + 8 : 9

Maximum (1, 9)

Minimum (- \frac{1}{3}, \frac{211}{27}), Maximum (1, 9)

e x t re m e x^{3} + y^{2} + 12 x y + 1

e x t re m e - \frac{\frac{40}{3}}{x ^{2}} + 0.54 x

e x t re m e f (x, y) = x \cdot e^{y}

e x t re m e f (x) = 4 θ - 6 sin (θ)

e x t re m e f (x, y) = x^{2} + y^{2} - 2 x + y