extreme y=x^2-11x+30

Lösung

extrempunkte

y = x^{2} - 11 x + 30

Minimum (\frac{11}{2}, - \frac{1}{4})

Schritte zur Lösung

f^{'} (x) = 2 x - 11

Intervalle finden:

Absteigend

: - \infty < x < \frac{11}{2},

Ansteigend

: \frac{11}{2} < x < \infty

Stecke

x = \frac{11}{2}

x^{2} - 11 x + 30 : - \frac{1}{4}

Minimum (\frac{11}{2}, - \frac{1}{4})

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