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Popular >

extreme x^2+(640)/x

Solution

extreme points

x^{2} + \frac{640}{x}

Solution

Minimum (435, 48 \cdot 5^{\frac{2}{3}})

Solution steps

f^{'} (x) = 2 x - \frac{640}{x ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 435,

Increasing

: 435 < x < \infty

Plug

x = 435

into

x^{2} + \frac{640}{x} : 48 \cdot 5^{\frac{2}{3}}

Minimum (435, 48 \cdot 5^{\frac{2}{3}})

Graph

Popular Examples

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extreme f(x)=3-5x^2 extreme points

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Frequently Asked Questions (FAQ)

What is the extreme x^2+(640)/x ?
The extreme x^2+(640)/x is Minimum(4\sqrt[3]{5},48*5^{2/3})