de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Funktionen >

extreme f(x)=x^3-7/2 x^2+2x-5

Lösung

extrempunkte

f (x) = x^{3} - \frac{7}{2} x^{2} + 2 x - 5

Lösung

Maximum (\frac{1}{3}, - \frac{253}{54}), Minimum (2, - 7)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 7 x + 2

Intervalle finden:

Ansteigend

: - \infty < x < \frac{1}{3},

Absteigend

: \frac{1}{3} < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = \frac{1}{3}

in

x^{3} - \frac{7}{2} x^{2} + 2 x - 5 : - \frac{253}{54}

Maximum (\frac{1}{3}, - \frac{253}{54})

Stecke

x = 2

in

x^{3} - \frac{7}{2} x^{2} + 2 x - 5 : - 7

Minimum (2, - 7)

Maximum (\frac{1}{3}, - \frac{253}{54}), Minimum (2, - 7)

Graph

Beliebte Beispiele

extreme f(x)=(t^2-4)^3

e x t re m e f (x) = (t^{2} - 4)^{3}

extreme x/(x^2+16),0<= x<= 8

e x t re m e \frac{x}{x ^{2} + 16}, 0 \leq x \leq 8

extreme f(x)=((x^2-5x+2))/(x-5)

e x t re m e f (x) = \frac{( x ^{2} - 5 x + 2 )}{x - 5}

extreme (8-x)(x+1)^2

e x t re m e (8 - x) (x + 1)^{2}

extreme f(x)=x^3+11x+10

e x t re m e f (x) = x^{3} + 11 x + 10