extreme (x-3)/(x^2-18x+81)

Lösung

extrempunkte

\frac{x - 3}{x ^{2} - 18 x + 81}

Minimum (- 3, - \frac{1}{24})

Schritte zur Lösung

f^{'} (x) = - \frac{x + 3}{( x - 9 ) ^{3}}

Intervalle finden:

Absteigend

: - \infty < x < - 3,

Ansteigend

: - 3 < x < 9,

Absteigend

: 9 < x < \infty

Stecke

x = - 3

\frac{x - 3}{x ^{2} - 18 x + 81} : - \frac{1}{24}

Minimum (- 3, - \frac{1}{24})

e x t re m e f (x) = x \cdot \frac{( 1 - x ) ^{2}}{( 1 + x ) ^{2}}

e x t re m e \frac{4 + x}{9 - x}, - 9 \leq x \leq 0

e x t re m e 333.7

e x t re m e f (x, y) = - 8 x^{2} - 3 y^{2} + 8 x - y + 2

e x t re m e f (x) = - \frac{13}{x ^{2} - 5 x + 35}