extreme f(x)=1-9x-6x^2-x^3

Lösung

extrempunkte

f (x) = 1 - 9 x - 6 x^{2} - x^{3}

Minimum (- 3, 1), Maximum (- 1, 5)

Schritte zur Lösung

f^{'} (x) = - 3 x^{2} - 12 x - 9

Intervalle finden:

Absteigend

: - \infty < x < - 3,

Ansteigend

: - 3 < x < - 1,

Absteigend

: - 1 < x < \infty

Stecke

x = - 3

1 - 9 x - 6 x^{2} - x^{3} : 1

Minimum (- 3, 1)

Stecke

x = - 1

1 - 9 x - 6 x^{2} - x^{3} : 5

Maximum (- 1, 5)

Minimum (- 3, 1), Maximum (- 1, 5)

e x t re m e y = \frac{4 x ^{2}}{x ^{2} - 4}

e x t re m e f (x, y) = x^{3} + 3 x y^{2} - 3 y^{2} + 3 x^{2} + 11

e x t re m e f (x, y) = \frac{1}{3 ^{- x^{2} - y^{2}} + 1}

e x t re m e f (x) = - sin^{2} (x), - π \leq x \leq π

e x t re m e f (x) = x (22 - 40 + 2 x) (\frac{40}{2} - x)