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Frequently Asked Questions (FAQ)
What is the extreme f(x)=(x^3)/3-3x^2+8x-2,0<= x<= 3 ?
- The extreme f(x)=(x^3)/3-3x^2+8x-2,0<= x<= 3 is Minimum(0,-2),Maximum(2, 14/3),Minimum(3,4)