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Frequently Asked Questions (FAQ)
What is the extreme f(x)=x^3-2x^2-4x+8,-1<= x<= 0 ?
- The extreme f(x)=x^3-2x^2-4x+8,-1<= x<= 0 is Minimum(-1,9),Maximum(-2/3 , 256/27),Minimum(0,8)