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Popular >

extreme y=x^2+2x-2

Solution

extreme points

y = x^{2} + 2 x - 2

Solution

Minimum (- 1, - 3)

Solution steps

f^{'} (x) = 2 x + 2

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{2} + 2 x - 2 : - 3

Minimum (- 1, - 3)

Popular Examples

extreme f(x,y)=98y^2+x^2-x^2y extreme points

f (x, y) = 98 y^{2} + x^{2} - x^{2} y

extreme f(x)=4cos(2x)-4,(0,2pi)extreme points

f (x) = 4 cos (2 x) - 4, (0, 2 π)

extreme f(x)=2x+9x^{2/9}extreme points

f (x) = 2 x + 9 x^{\frac{2}{9}}

extreme f(x)=sqrt(x)ln(6x)extreme points

f (x) = x ln (6 x)

extreme f(x)=-x^3+3x^2+24x+2 extreme points

f (x) = - x^{3} + 3 x^{2} + 24 x + 2

Frequently Asked Questions (FAQ)

What is the extreme y=x^2+2x-2 ?
The extreme y=x^2+2x-2 is Minimum(-1,-3)