What is the extreme f(x)=(x^5-5x)/5 ?

The extreme f(x)=(x^5-5x)/5 is Maximum(-1, 4/5),Minimum(1,-4/5)

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extreme f(x)=(x^5-5x)/5

extreme points

f (x) = \frac{x ^{5} - 5 x}{5}

Maximum (- 1, \frac{4}{5}), Minimum (1, - \frac{4}{5})

Solution steps

f^{'} (x) = x^{4} - 1

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

\frac{x ^{5} - 5 x}{5} : \frac{4}{5}

Maximum (- 1, \frac{4}{5})

Plug

x = 1

into

\frac{x ^{5} - 5 x}{5} : - \frac{4}{5}

Minimum (1, - \frac{4}{5})

Maximum (- 1, \frac{4}{5}), Minimum (1, - \frac{4}{5})

f (x) = (x - 3) (x + 1) (x + 5)

f (x) = 3 - x^{2}

f (x) = 3 x^{2} - 7 x + 2

x^{2} - 2 x + 9

q (x, y) = - 5 x^{2} - 8 y^{2} - 2 x y + 42 x + 102 y

What is the extreme f(x)=(x^5-5x)/5 ?
The extreme f(x)=(x^5-5x)/5 is Maximum(-1, 4/5),Minimum(1,-4/5)