What is the domain of x/(ln(x-1)-1) ?

The domain of x/(ln(x-1)-1) is 1 e+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of x/(ln(x-1)-1)

domain

\frac{x}{ln ( x - 1 ) - 1}

1 < x < e + 1 or x > e + 1

Solution steps

Find positive values for logs:

x > 1

Find undefined (singularity) points:

x = e + 1

Combine real regions and undefined points for final function domain

1 < x < e + 1 or x > e + 1

f (x) = \frac{x + 1}{x ^{2} - 9 x + 8}

f (x) = - 3 x^{2} + x

\frac{x + 5}{3}

f (x) = cos (x - 7) + 4

f (x, y) = ln (x - 6)

What is the domain of x/(ln(x-1)-1) ?
The domain of x/(ln(x-1)-1) is 1<x<e+1\lor x>e+1